Question
Find the mean deviation about the mean for the data 4,7,8,9,10,12,13,17
BITSAT
Mathematics
Statistics
2023
BITSAT 2023 (Memory Based Paper 1)
BITSAT Mathematics Question (2023) — Solution
Options
- A. 3
- B. 24
- C. 10
- D. 8
Answer
A. 3
Step-by-step solution
Arithmetic mean x of 4,7,8,9,10,12,13, 17 is x = 4+7+8+9+10+12+13+17 8 = 80 8 =10 |x_i- x |=6+3+2+1+0+2+3+7=24 Mean deviation about mean = M.D. ( x )= |x_i- x | n = 24 8 =3
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