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BITSAT Mathematics Straight Lines 2021 BITSAT 2021

BITSAT Mathematics Question (2021) — Solution

Question

The distance between the parallel lines 3 x-4 y+7=0 and 3 x-4 y+5=0 is a b . Value of a+b is

Options

  1. A. 2
  2. B. 5
  3. C. 7
  4. D. 3

Answer

C. 7

Step-by-step solution

Given parallel lines are 3 x-4 y+7=0 and 3 x-4 y+5=0 Required distance = |7-5| (3)^ 2 +(-4)^ 2 = 2 5 a=2, b=5

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