BITSAT Mathematics Question (2023) — Solution

Step-by-step solution

One vertex of square is (-4,5) and equation of one diagonal is 7 x-y+8=0 Diagonal of a square are perpendicular and bisect each other Let the equation of the other diagonal be y=m x+ c where m is the slope of the line and c is the y -intercept. Since this line passes through (-4,5) Since this line is at right angle to the line 7 x-y+8=0 or y=7 x+8, having slope =7, 7 m =-1 or m = -1 7 Putting this value of m in equation (i) we get 5=-4 ( -1 7 )+c or 5= 4 7 +c or c=5- 4 7 = 31 7 Hence equation of the other diagonal is y=- 1 7 x+ 31 7 or 7 y=-x+31 or x+7 y-31=0 or x+7 y=31