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BITSAT Mathematics Vector Algebra 2021 BITSAT 2021

BITSAT Mathematics Question (2021) — Solution

Question

If a is a vector of magnitude 50 , collinear with the vector b =6 i -8 j - 15 2 k and makes an acute angle with the positive direction of Z - axis, then a is equal to

Options

  1. A. -24 i +32 j +30 k
  2. B. 24 i -32 j -30 k
  3. C. -12 i +16 j -15 k
  4. D. 12 i -16 j -15 k

Answer

A. -24 i +32 j +30 k

Step-by-step solution

Since a =m b for some scalar m i.e., array l a =m (6 i -8 j - 15 2 k ) \\ |a|=|m| 36+64+ 225 4 \\ 50= 25 2 |m| \\ |m|=4 \\ m= 4 array Since, a makes an acute angle with the positive direction of Z - axis, so its z component must be positive and hence, m must be -4. a=-4 (6 i +8 j - 15 2 k )=-24 i +32 j +30 k

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