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BITSAT Mathematics Vector Algebra 2022 BITSAT 2022

BITSAT Mathematics Question (2022) — Solution

Question

107. u and v are two non-collinear unit vectors such that | u + v 2 + u v |=1. Then the value of | u v | is equal to

Options

  1. A. | u + v 2 |
  2. B. | u + v |
  3. C. | u - v |
  4. D. | u - v 2 |

Answer

D. | u - v 2 |

Step-by-step solution

Given that, | u + v 2 + u v |=1 array ll & | u + v 2 + u v |^2=1 \\ & 2+2 4 + ^2 =1 \\ & [ u ( u v )= v ( u v )=0] \\ & ^2 2 = 2 \\ & =n 2 , n z \\ & = 2 3 array | u v |= 2 3 = 3 = | u - v 2 |

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Related: Mathematics — Vector Algebra · All PYQ Banks