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BITSAT Physics Alternating Current 2022 BITSAT 2022

BITSAT Physics Question (2022) — Solution

Question

In the circuit shown in the figure, the AC source gives a voltage V=20 (2000 t) neglecting source resistance, the voltmeter and ammeter reading will be

Options

  1. A. 0 ~V , 0.47 ~A
  2. B. 282 ~V , 1.41 ~A
  3. C. 1.41 ~V , 0.47 ~A
  4. D. 15 ~V , 837 ~A

Answer

B. 282 ~V , 1.41 ~A

Step-by-step solution

Given, R_1=8 aligned R_2 & =2 \\ L & =5 mH \\ C & =50 F aligned and V_0=20 (2000 t) Impedance, Z= R^2+ (X_L-X_C )^2 As, here, X_L= L=2000 5 10^ -3 =10 Similarly, X_L= 1 C = 1 2000 50 10^ -6 =10 X_L=X_C, Hence, i_ = V_0 Z = 20 (8+2) =2 ~A Hence, i_ rms = i_ 2 = 2 2 =1.41 ~A and aligned V & =R_2 i_ rms =1.41 2 \\ & =282 ~V aligned

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