Question
An alternating voltage V(t)=220 100 t volt is applied to a purely resistive load of 50 . The time taken for the current to rise from half of the peak value to the peak value is:
An alternating voltage V(t)=220 100 t volt is applied to a purely resistive load of 50 . The time taken for the current to rise from half of the peak value to the peak value is:
B. 3.3 ms
Rising half to peak t=T / 6 t = 2 6 = 3 = 300 = 1 300 =3.3 ~ms Here =100 rad / s
Related: Physics — Alternating Current · All PYQ Banks