Question
The stopping potential (V_0 ) versus frequency (v) of a graph for photoelectric effect in a metal. From the graph, the planck's constant (h) is.
BITSAT
Physics
Atomic Physics
2022
BITSAT 2022
BITSAT Physics Question (2022) — Solution
Options
- A. 6.60 10^ -34 ~J - s
- B. 6.69 10^ -34 ~J - s
- C. 6.62 10^ -34 ~J - s
- D. 6.63 10^ -34 ~J - s
Answer
A. 6.60 10^ -34 ~J - s
Step-by-step solution
aligned e V_0=h (v-v_0 ) & =h v-h v_0 \\ V_0 & = ( h e ) v- ( h e ) v_0 (i) aligned From Eq. (i), it follows that the slope of the graph is h e . Therefore, aligned h=e slope & =1.6 10^ -19 165-0 (8-4) 10^ 15 \\ & = 1.6 10^ -19 16.5 4 10^ 15 =6.6 10^ -34 ~J - s . aligned
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