Question
The ratio of the shortest wavelength of Balmer series to the shortest wavelength of Lyman series for hydrogen atom is:
BITSAT
Physics
Atomic Physics
2024
BITSAT 2024 (Memory Based Paper 2)
BITSAT Physics Question (2024) — Solution
Options
- A. 4: 1
- B. 1: 2
- C. 1: 4
- D. 2: 1
Answer
A. 4: 1
Step-by-step solution
Wavelength of H -atom is 1 = Rz ^2 ( 1 n _1^2 - 1 n _2^2 ) Shortest wavelength for Balmer series: 1 _B = Rz ^2 ( 1 2^2 - 1 ) Shortest wavelength for Lyman series: 1 _ L = Rz ^2 ( 1 1^2 - 1 ) ....(ii) Dividing eq. (i) and (ii), _ A : _1=4: 1
Related: Physics — Atomic Physics · All PYQ Banks