Question
A ball falling freely from a height of 4.9 ~m / s , hits a horizontal surface. If e= 3 4 , then the ball will hit the surface, second time after
BITSAT
Physics
Center of Mass Momentum and Collision
2024
BITSAT 2024 (Memory Based Paper 3)
BITSAT Physics Question (2024) — Solution
Options
- A. 1.0 s
- B. 1.5 s
- C. 2.0 s
- D. 3.0 s
Answer
B. 1.5 s
Step-by-step solution
aligned Velocity on hitting the surface & = 2 9.8 4.9 \\ & =9.8 ~m / s aligned Velocity after first bounce, v= 3 4 9.8 Time taken from first bounce to the second bounce = 2 v g =2 3 4 9.8 1 9.8 =1.5 ~s
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