Question
A wire of a certain material is stretched slowly by ten per cent. Its new resistance and specific resistance become respectively:
BITSAT
Physics
Current Electricity
2021
BITSAT 2021
BITSAT Physics Question (2021) — Solution
Options
- A. 1.2 times, 1.3 times
- B. 1.21 times, same
- C. both remain the same
- D. 1.1 times, 1.1 times
Answer
B. 1.21 times, same
Step-by-step solution
\( R = l A \) Now, \(1=1+ 1 10 = 111 10 \) and therefore, \( A = 10 ~A 11 \) So \( R ^ = p ( 111 10 ) 10 ~A 11 = l A (11)^ 2 (10)^ 2 =1.21 R \) Now resistance becomes \(1.21\) times of initial and specific resistance is the intrinsic property so remains same.
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