An electric current I enters and leaves a uniform circular wire of radius r through diametrically opposite points. A charged particle q moves along the axis of circular wire passes through its centre at speed v. The magnetic force on the particle when it passes through the centre has a magnitude.

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Correct answer: D. 0

Force on a moving charged particle in uniform magnetic field F=B q v Since, charge particle moves along the axis of circular current carrying loop, therefore, =0^ or 180^ When =0^ ; F=B q v 0^ F=0 When =180^ , F=B q u 180^ F=0

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