Question
In the given circuit, E_1=E_2=E_3=2 ~V and R_1=R_2=4 , then current flowing through the branch A B is
BITSAT
Physics
Current Electricity
2024
BITSAT 2024 (Memory Based Paper 3)
BITSAT Physics Question (2024) — Solution
Options
- A. zero
- B. 2 A from A and B
- C. 2 A from B to A
- D. 5 A from B to B
Answer
B. 2 A from A and B
Step-by-step solution
The given circuit can be redrawn as, where, equivalent emf of the combination, aligned E_ eq & = E_1 R_1+E_2 R_2 R_1+R_2 \\ & = 2 4+2 4 4+4 =2 ~V aligned and R_ e q = R_1 R_2 R_1+R_2 = 4 4 4+4 = 16 8 =2 Net emf of the circuit, aligned E^ & =E_2+E_ eq \\ & =2+2 \\ & =4 ~V aligned Current flowing through branch A B, I= E^ R_ e q = 4 2 =2 ~A Clearly from figure, it is clear that direction of current is from point A to B clockwise is loop.
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