Question
The de-Broglie wavelength of an electron moving with a velocity c 3 (c=3 10^8 ~m / s ) is equal to the wavelength of photon. The ratio of the kinetic energies of electron and photon is
BITSAT
Physics
Dual Nature of Matter
2022
BITSAT 2022
BITSAT Physics Question (2022) — Solution
Options
- A. 1: 4
- B. 1: 3
- C. 1: 2
- D. 2: 1
Answer
B. 1: 3
Step-by-step solution
The de-Broglie wavelength, = h m v Here, _e= h m_e c 3 and _p= h m_p c Given, _e= _p So, h m_e c 3 = h m_p c m_e m_p =3 Ratio of KE = K_e K_p = 1 2 m_e v_e^2 1 2 m_p v_p^2 = 1 3 ( m_e m_p =3, v_e= c 3 . and .v_p=c )
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