BITSAT
Physics
Electromagnetic Waves
2024
BITSAT 2024 (Memory Based Paper 3)
BITSAT Physics Question (2024) — Solution
Question
A parallel plate capacitor consists of two circular plates of radius R=0.1 ~m . They are separated by a short distance. If electric field between the capacitor plates changes as d E d t =6 10^ 13 ~V ~m s , then the value of displacement current is
Options
- A. 15.25 A
- B. 6.25 A
- C. 16.67 A
- D. 4.69 A
Step-by-step solution
Given, area of plates, A= R^2=3.14 (0.1)^2 ~m ^2 and d E d t =6 10^ 13 ~V ~m s Displacement current between the plates, aligned I_d & = _0 d d t \\ I_d & = _0 A ( d E d t ) [ d d t =A d E d t ] \\ & =8.85 10^ -12 3.14 (0.1)^2 6 10^ 13 \\ I_d & =16.67 ~A aligned
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