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BITSAT Physics Electrostatics 2021 BITSAT 2021

BITSAT Physics Question (2021) — Solution

Question

The electric potential V is given as a function of distance ( metre ) by V= (5 x^ 2 +10 x-4 ) volt. Question: Value of electric field at x=1 ~m is

Options

  1. A. -23 ~V / m
  2. B. 11 ~V / m
  3. C. 6 ~V / m
  4. D. -20 ~V / m

Answer

D. -20 ~V / m

Step-by-step solution

V =5 x^ 2 +10 x-4 E = - dV dx =-(10 x+10) At x=1 m, E =-20 ~V / m

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