Question
If two charges q_1 and q_2 are separated with distance ' d ' and placed in a medium of dielectric constant K. What will be the equivalent distance between charges in air for the same electrostatic force ?
BITSAT
Physics
Electrostatics
2024
BITSAT 2024 (Memory Based Paper 2)
BITSAT Physics Question (2024) — Solution
Options
- A. d K
- B. K d
- C. 1.5 d K
- D. 2 d K
Answer
A. d K
Step-by-step solution
As. F(air)=F(medium) 1 4 _0 q _1 q _2 ~d _ air ^2 = 1 ~K 1 4 _0 q _1 q _2 ~d ^2 ~d _ air = d K
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