Question
Two identical particles each of mass ' m ' go round a circle of radius a under the action of their mutual gravitational attraction. The angular speed of each particle will be:
BITSAT
Physics
Gravitation
2023
BITSAT 2023 (Memory Based Paper 2)
BITSAT Physics Question (2023) — Solution
Options
- A. G m 2 a^3
- B. Gm 8 a ^3
- C. G m 4 a^3
- D. G m a^3
Answer
C. G m 4 a^3
Step-by-step solution
Radius of circle, r = a Centrifugal force, F=m ^2 r aligned & Gmm (2 a )^2 = m ^2 a \\ & ( F = G M M _2 ~d ) aligned Here M_1=m ; M_2=m and d=2 a angular speed, = G m 4 a^3
Related: Physics — Gravitation · All PYQ Banks