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BITSAT Physics Gravitation 2023 BITSAT 2023 (Memory Based Paper 2)

BITSAT Physics Question (2023) — Solution

Question

If V is the gravitational potential due to sphere of uniform density on it's surface, then it's value at the center of sphere will be:

Options

  1. A. 3 V 2
  2. B. V
  3. C. 4 3 ~V
  4. D. V 2

Answer

A. 3 V 2

Step-by-step solution

Potential due to sphere V = GM 2 R ^3 (3 R ^2- r ^2 ) At surface r=R V= ( G M R ) At centre, r=0 V _0= 3 GM 2 R = ( 3 ~V 2 )

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