The kinetic energy of a satellite in its orbit around the earth is E . What should be the kinetic energy of the satellite so as to enable it to escape from the gravitational pull of the earth?

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Correct answer: B. 2 E

We know that v_e= 2 v_0, where v _0 is orbital velocity. K.E. in the orbit, E= 1 2 M v_0 ^2 K.E. to escape E= 1 2 M v_e^2= 1 2 M (2 v_0 ^2 ) = 1 2 M v_0^2 2=2 E

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