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BITSAT Physics Laws of Motion 2021 BITSAT 2021

BITSAT Physics Question (2021) — Solution

Question

A ball of mass 0.2 ~kg is thrown vertically upwards by applying a force by hand. If the hand moves 0.2 ~m while applying the force and the ball goes upto 2 ~m height further, find the magnitude of the force. (Consider .g=10 ~m / s ^ 2 ).

Options

  1. A. 4 ~N
  2. B. 16 ~N
  3. C. 20 ~N
  4. D. 22 ~N

Answer

D. 22 ~N

Step-by-step solution

Let the velocity of the ball just when it leaves the hand is u then applying, array l v^ 2 -u^ 2 =2 a for upward journey \\ -u^ 2 =2(-10) 2 \\ u^ 2 =40 array Again applying v^ 2 -u^ 2 =2 a s for the upward journey of the ball, when the ball is in the hands of the thrower, array l v^ 2 -u^ 2 =2 a s \\ 40-0=2(a) 0.2 \\ a=100 ~m / s ^ 2 \\ F =m a=0.2 100=20 ~N \\ N -m g=20 \\ N =20+2=22 ~N array

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