Question
What will be the acceleration due to gravity at a depth d, where g is acceleration due to gravity on the surface of earth?
BITSAT
Physics
Laws of Motion
2022
BITSAT 2022
BITSAT Physics Question (2022) — Solution
Options
- A. g [1+ d R ]^2
- B. g [1- 2 d R ]
- C. g [1- d R ]^2
- D. g [1- d R ]
Answer
D. g [1- d R ]
Step-by-step solution
Acceleration due to gravity at the surface of earth, g= G M R^2 = 4 3 G R [ M= 4 3 R^3 ] Where, = density of earth. Acceleration due to gravity at depth d from the surface of earth, g^ = 4 3 G(R-d) From Eqs. (i) and (ii), we get g^ =g [1- d R ]
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