Question
At any instant the velocity of a particle of mass 500 ~g is (2 t i +3 t^2 j ) ms ^ -1 . If the force acting on the particle at t=1 s is ( i +x j ) N. Then the value of x will be:
BITSAT
Physics
Laws of Motion
2023
BITSAT 2023 (Memory Based Paper 1)
BITSAT Physics Question (2023) — Solution
Options
- A. 3
- B. 4
- C. 6
- D. 2
Answer
A. 3
Step-by-step solution
Mass of particle, m =500 ~g =0.5 ~kg velocity of a particle, v =2 t i +3 t^2 j a = d v dt =2 i +6 t j at t =1, a =2 i +6 j Force acting on the particle, F = ma =0.5(2 i +6 j )= i +3 j F = i +x j Hence x=3
Related: Physics — Laws of Motion · All PYQ Banks