A solenoid of 1200 turns is wound uniformly in a single layer on a glass tube 2 ~m long and 0.2 ~m in diameter. The magnetic intensity at the center of the solenoid when a current of 2 A flows through it is:

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Correct answer: B. 1.2 10^3 Am ^ -1

Given that number of turns, n=1200 Current, I =2 ~A Magnetic field at centre inside the solenoid is given by, B = _0 nI So magnetic intensity at centre of the solenoid, aligned & H = B _0 = nI = ( 1200 2 )(2) ( B = _0 H ) \ & H =1.2 10^3 Am ^ -1 aligned

BITSAT Physics Question (2023) — Solution

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