A cube of ice floats partly in water and partly in kerosene oil. The radio of volume of ice immersed in water to that in kerosene oil (specific gravity of Kerosene oil =0.8, specific gravity of ice =0.9)

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Correct answer: D. 1: 1

Let V_1 be, the volume immersed in water. V_2 be the volume immersed in oil. In equilibrium condition, v_1 _w g+v_2 _0 g= (v_1+v_2 ) _e g v_1+ v_2 _0 _w = (v_1+v_2 ) _c _w v_1+0.8 v_2=0.9 v_1+0.9 v_2 0.1 v_1=0.1 v_2 v_1: v_2=1: 1

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