Question
The distance travelled by a particle starting from rest and moving with an acceleration 4 3 ~ms ^ -2 , in the third second is:
BITSAT
Physics
Motion In One Dimension
2024
BITSAT 2024 (Memory Based Paper 1)
BITSAT Physics Question (2024) — Solution
Options
- A. 6 m
- B. 4 m
- C. 10 3 ~m
- D. 19 3 ~m
Answer
C. 10 3 ~m
Step-by-step solution
Distance travelled in the nth second is given by t _ n = u + a 2 (2 n -1) put u =0, a = 4 3 ~ms ^ -2 , n =3 d=0+ 4 3 2 (2 3-1)= 4 6 5= 10 3 m
Related: Physics — Motion In One Dimension · All PYQ Banks