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BITSAT Physics Motion In Two Dimensions 2022 BITSAT 2022

BITSAT Physics Question (2022) — Solution

Question

A projectile is projected with the velocity of (3 i +4 j ) m / s . The horizontal range of the projectile will be

Options

  1. A. 1.2 ~m
  2. B. 2.4 ~m
  3. C. 3.6 ~m
  4. D. 4.5 ~m

Answer

B. 2.4 ~m

Step-by-step solution

Given, v =3 i +4 j v=| v |= 3^2+4^2 v=5 ~m / s From figure, = 4 5 and = 3 5 R= v^2 2 g = v^2 2 g = 5 5 2 4 5 3 5 10 =24 ~m

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