A projectile is projected at 30^ from horizontal with initial velocity 40 ~ms ^ -1 . The velocity of the projectile at t =2 ~s from the start will be: (Given g =10 ~m / s ^2 )

Question

Quantrex Academy · Accepted Answer

Correct answer: A. 20 3 ~ms ^ -1

Given, Initial velocity of projectile, u=40 ~m / s Angle, =30^ Time of flight T = 2 u g = 2 40 1 10 2 =45 ( g =10 ~m / s ^2 ) It means projectile is at maximum height at t= 2 ~s . At maximum height vertical component of velocity is zero. aligned & Velocity at t =2 ~s = V _ x = u =40 30^ \ & =20 3 ~ms ^ -1 . \ & aligned

BITSAT Physics Question (2023) — Solution

Question

Options

Answer

Step-by-step solution