A particle of mass m is projected with a velocity ' u ' making an angle of 30^ with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height h is:

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Correct answer: A. 3 16 mu ^3 ~g

Angular momentum, L=m v H=m u 30 H =m u 30^ u^2 ^2 2 g [ H= u^2 ^2 2 g ] = m u^3 2 g 3 2 ( 1 2 )^2= 3 m u^3 16 g

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