Question
A particle executes SHM of amplitude A. The distance from the mean position when it's kinetic energy becomes equal to its potential energy is
A particle executes SHM of amplitude A. The distance from the mean position when it's kinetic energy becomes equal to its potential energy is
C. 1 2 ~A
Let the distance from the mean position is X . Given KE = PE So, 1 2 M ^2 (A^2-x^2 )= 1 2 M ^2 x^2 A^2-x^2=x^2 A^2=2 2 x = A 2
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