A particle executes simple harmonic motion between x=-A and x=+A. If time taken by particle to go from x=0 to A 2 is 2 s; then time taken by particle in going from x= A 2 to A is:

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Correct answer: D. 4 s

Let time from 0 to A / 2 is t _1 and from A / 2 to A is t _2 From the standard equation of SHM, A 2 = A ( t _1 ) t_1= ^ -1 ( 1 2 )= 6 ....(i) Using x=A_0 t again A=A (t_1+t_2 ) (t_1+t_2 )= ^ -1 (1)= 2 Using (i) t_2= 2 - 6 = 3 .....(ii) Dividing equation (i) by (ii) we get t_1 t_2 = 1 2 t_2=2 t_1=2 2=4 sec

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