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BITSAT Physics Rotational Motion 2024 BITSAT 2024 (Memory Based Paper 3)

BITSAT Physics Question (2024) — Solution

Question

The moment of inertia of a cube of mass m and side a about one of its edges is equal to

Options

  1. A. 2 3 m a^2
  2. B. 4 3 m a^2
  3. C. 3 m a^2
  4. D. 8 3 m a^2

Answer

A. 2 3 m a^2

Step-by-step solution

From theorem of perpendicular axes, we have aligned I & =I_C+m ( a 2 )^2 \\ & = [ m a^2 12 + m a^2 12 ]+ m a^2 2 \\ & = 2 3 m a^2 aligned

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