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BITSAT Physics Thermal Properties of Matter 2021 BITSAT 2021

BITSAT Physics Question (2021) — Solution

Question

The two ends of a rod of length L and a uniform crosssectional area A are kept at two temperatures T_ 1 and T _ 2 ( ~T _ 1 > T _ 2 ). The rate of heat transfer, dQ dt through the rod in a steady state is given by:

Options

  1. A. k (T_ 1 -T_ 2 ) L A
  2. B. k L A (T_ 1 -T_ 2 )
  3. C. k A (T_ 1 -T_ 2 ) L
  4. D. k L (T_ 1 -T_ 2 ) A

Answer

C. k A (T_ 1 -T_ 2 ) L

Step-by-step solution

dQ dt = kA ( T _ 1 - T _ 2 ) L [ ( T _ 1 - T _ 2 ) . is the temperature difference ]

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