Question
Young's double slit experiment is performed in a medium of refractive index of 1.33 . The maximum intensity is I_0. The intensity at a point on the screen, where path difference between the light coming out from slits is 4 , is
BITSAT
Physics
Wave Optics
2024
BITSAT 2024 (Memory Based Paper 3)
BITSAT Physics Question (2024) — Solution
Options
- A. 0
- B. I_0 2
- C. 3 I_0 8
- D. 2 I_0 3
Answer
B. I_0 2
Step-by-step solution
Given, path difference, x= 4 Phase difference, = ( 2 ) (Path difference) = 2 4 = 2 ...(i) It is given that, maximum intensity is I_0. So, intensity at a point on the screen, where phase difference is given by aligned I & =I_0 ^2 ( 2 ) \\ & =I_0 ^2 ( / 2 2 ) [ using Eq.(i) ] \\ & =I_0 ( 1 2 )^2 \\ & = I_0 2 aligned
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