Question
A microwave of wavelength 2.0 cm falls normally on a slit of width 4.0 cm . The angular spread of the central maxima of the diffraction pattern obtained on a screen 1.5 m away from the slit, will be:
BITSAT
Physics
Wave Optics
2024
BITSAT 2024 (Memory Based Paper 2)
BITSAT Physics Question (2024) — Solution
Options
- A. 60^
- B. 45^
- C. 15^
- D. 30^
Answer
A. 60^
Step-by-step solution
Condition for minima is d = n For Ist minimad = = a = 2 4 = 1 2 =30^ Angular spread =2 =60^
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