A spherical ball of mass 20 kg is stationary at the top of a hill of height 100 m . It rolls down a smooth surface to the ground, then climbs up another hill of height 30 m and finally rolls down to a horizontal base at a height of 20 m above the ground. The velocity attained by the ball is

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Correct answer: B. 40 ~m / s

Using conservation of energy, m (10 100)= m ( 1 2 v ^2+10 20 ) or 1 2 v^2=800 or v= 1600 =40 ~m / s

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