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BITSAT Physics Work Power Energy 2024 BITSAT 2024 (Memory Based Paper 1)

BITSAT Physics Question (2024) — Solution

Question

A particle of mass 2 kg is on a smooth horizontal table and moves in a circular path of radius 0.6 m . The height of the table from the ground is 0.8 m . If the angular speed of the particle is 12 rad s ^ -1 , the magnitude of its angular momentum about a point on the ground right under the centre of the circle is

Options

  1. A. 14.4 ~kg ~m ^2 ~s ^ -1
  2. B. 8.64 ~kg ~m ^2 ~s ^ -1
  3. C. 20.16 ~kg ~m ^2 ~s ^ -1
  4. D. 11.52 ~kg ~m ^2 ~s ^ -1

Answer

A. 14.4 ~kg ~m ^2 ~s ^ -1

Step-by-step solution

Angular momentum L_0= mvr 90^ =2 0.6 12 1 1 [ . As V=r , . Sin 90^ =1 ] So, L_0=14.4 kgm ^2 / s

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