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JEE Advanced Chemistry Aldehydes and Ketones 2024 JEE Advanced 2024 (Paper 2)

JEE Advanced Chemistry Question (2024) — Solution

Question

Paragraph I: An organic compound \( P \) with molecular formula \( C _5 H _ 18 O _2\) decolorizes bromine water and also shows positive iodoform test. \( P \) on ozonolysis followed by treatment with \( H _2 O _2\) gives \( Q \) and \( R \). While compound \( Q \) shows positive iodoform test, compound \( R \) does not give positive iodoform test. \( Q \) and \( R \) on oxidation with pyridinium chlorochromate (PCC) followed by heating give \( S \) and \( T \), respectively. Both \( S \) and \( T \) show positive iodoform test. Complete copolymerization of 500 moles of \( Q \) and 500 moles of \( R \) gives one mole of a single acyclic copolymer \( U \). [Given, atomic mass: \( H =1, C =12, O =16\)] Question: The molecular weight of U is

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

S~ \& ~T shows + ve idoform test. Rmf C _5 H _ 10 O _3 (M. wt )_ R =70+48=118 Q mf C _4 H _8 O _3( M . wt )_ Q =56+48=104 500 mole Q +500 mole R [ polymer ] Condensation aligned U molecular weight & =500 118+500 104-999 18=500 222-17982 \\ & =111000-17982=93018 aligned Ans. is 93018

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