Question
Which of the following statement(s) is(are) true?
JEE Advanced
Chemistry
Biomolecules
2019
JEE Advanced 2019 (Paper 1)
JEE Advanced Chemistry Question (2019) — Solution
Options
- A. Oxidation of glucose with bromine water gives glutamic acid
- B. The two six-membered cyclic hemiacetal forms of D - + - glucose are called anomers
- C. Hydrolysis of sucrose gives dextrorotatory glucose and levorotatory fructose
- D. Monosaccharides cannot be hydrolysed to give polyhydroxy aldehydes and ketones
Answer
D. Monosaccharides cannot be hydrolysed to give polyhydroxy aldehydes and ketones
Step-by-step solution
→ Glucose → [ 0 ] Br 2 -H 2 O Glycolic acid → ∝ - Δ - Glucose and β - D Glucose → Hydrolysis of sucrose given dextrorotatory glucose and levorotatory fructose, → Monosaccharide cannot be hydrolyzed to give polyhydroxy aldehyde and ketones.
Related: Chemistry — Biomolecules · All PYQ Banks