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JEE Advanced Chemistry Biomolecules 2024 JEE Advanced 2024 (Paper 2)

JEE Advanced Chemistry Question (2024) — Solution

Question

For a double strand DNA, one strand is given below: The amount of energy required to split the double strand DNA into two single strands is _______ kcal mol ^ -1 . [Given: Average energy per H -bond for A-T base pair =1.0 kcal mol ^ -1 , G - C base pair =1.5 kcal mol ^ -1 , and A-U base pair =1.25 kcal mol ^ -1 . Ignore electrostatic repulsion between the phosphate groups.]

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

A = T 2 H -bond G C 3 H -bond Number of A = T pair =7 Number of G C pair =6 Number of H-bond involve in A = T =7 2=14 Number of H -bond involve in G C =6 3=18 Energy required for A = T =14 1=14 Energy required for G C =18 1.5=27 Total energy required 14+27=41

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