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JEE Advanced Chemistry Chemical Kinetics 2019 JEE Advanced 2019 (Paper 1)

JEE Advanced Chemistry Question (2019) — Solution

Question

In the decay sequence: U 92 238 → - x 1 T h 90 234 → - x 2 P a 91 234 → - x 3 Z   234 → - x 4 T h 90 234 x 1 ,   x 2 ,   x 3 and x 4 are the particles/ radiation emitted by the respective isotopes. The correct option(s) is/are:

Options

  1. A. Z is an isotope of uranium.
  2. B. x 2 is β - .
  3. C. x 1 will deflect towards the negatively charged plate.
  4. D. x 3 is γ -ray.

Answer

C. x 1 will deflect towards the negatively charged plate.

Step-by-step solution

I.e., x 1 = α , x 2 = β , x 3 = β and x 4 = α .

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Related: Chemistry — Chemical Kinetics · All PYQ Banks