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JEE Advanced Chemistry Classification of Elements and Periodicity in Properties 2020 JEE Advanced 2020 (Paper 2)

JEE Advanced Chemistry Question (2020) — Solution

Question

The 1 st , 2 nd and the 3 rd ionization enthalpies, I 1 ,   I 2  and  I 3 , of four atoms with atomic numbers  n ,   n + 1 ,   n + 2 , and n + 3 , where n < 10 , are tabulated below. What is the value of n ? Atomic number Ionization Enthalpy (kJ/mol)   I 1 I 2 I 3 n 1681 3374 6050 n + 1 2081 3952 6122 n + 2 496 4562 6910 n + 3 738 1451 7733  

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

From given data ( n + 2 ) atom is alkali metal which is sodium. As  n + 2 = 11 So,  n = 9

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