JEE Advanced
Chemistry
d and f Block Elements
2019
JEE Advanced 2019 (Paper 2)
JEE Advanced Chemistry Question (2019) — Solution
Question
Consider the following reactions (unbalanced) Z n + H o t   c o n c .   H 2 S O 4 → G + R + X Z n + c o n c .   N a O H → T + Q G + H 2 S + N H 4 O H → Z a   p r e c i p i t a t e + X + Y Choose the correct option(s).
Options
- A. The oxidation state of Z n in T is + 1
- B. Bond order of Q is 1 in its ground state
- C. Z is dirty white in colour
- D. R is a V -shaped molecule
Answer
D. R is a V -shaped molecule
Step-by-step solution
Zn + H 2 SO 4 Hot&Conc. → ZnSO 4 N + SO 2 ® + H 2 O X Zn + 2NaOH Conc. → NaZnO 2 T + H 2 Q ZnSO 4 + H 2 S + NH 4 OH → ZnS S + H 2 O X + NH 4 2 SO 4 Y
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Related: Chemistry — d and f Block Elements · All PYQ Banks