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JEE Advanced Chemistry d and f Block Elements 2019 JEE Advanced 2019 (Paper 2)

JEE Advanced Chemistry Question (2019) — Solution

Question

Consider the following reactions (unbalanced) Z n + H o t   c o n c .   H 2 S O 4 → G + R + X Z n + c o n c .   N a O H → T + Q G + H 2 S + N H 4 O H → Z a   p r e c i p i t a t e + X + Y Choose the correct option(s).

Options

  1. A. The oxidation state of Z n in T is + 1
  2. B. Bond order of Q is 1 in its ground state
  3. C. Z is dirty white in colour
  4. D. R is a V -shaped molecule

Answer

D. R is a V -shaped molecule

Step-by-step solution

Zn + H 2 SO 4 Hot&Conc. → ZnSO 4 N + SO 2 ® + H 2 O X Zn + 2NaOH Conc. → NaZnO 2 T + H 2 Q ZnSO 4 + H 2 S + NH 4 OH → ZnS S + H 2 O X + NH 4 2 SO 4 Y

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