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JEE Advanced Chemistry d and f Block Elements 2021 JEE Advanced 2021 (Paper 2)

JEE Advanced Chemistry Question (2021) — Solution

Question

Paragraph: The reaction of K _ 3 [ Fe ( CN )_ 6 ] with freshly prepared FeSO _ 4 solution produces a dark blue precipitate called Turnbull's blue. Reaction of K _ 4 [ Fe ( CN )_ 6 ] with the FeSO _ 4 solution in complete absence of air produces a white precipitate X , which turns blue in air. Mixing the FeSO _ 4 solution with NaNO _ 3 , followed by a slow addition of concentrated H _ 2 SO _ 4 through the side of the test tube produces a brown ring. Question: Precipitate X is

Options

  1. A. Fe 4 Fe CN 6 3
  2. B. Fe Fe CN 6
  3. C. K 2 Fe Fe CN 6
  4. D. KFe Fe CN 6

Answer

C. K 2 Fe Fe CN 6

Solution

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