Quantrex Academy · Free JEE Advanced PYQ solutions
JEE Advanced Chemistry Electrochemistry 2021 JEE Advanced 2021 (Paper 2)

JEE Advanced Chemistry Question (2021) — Solution

Question

At 298 ~K , the limiting molar conductivity of a weak monobasic acid is 4 10^ 2 ~S ~cm ^ 2 ~mol ^ -1 . At 298 ~K , for an aqueous solution of the acid the degree of dissociation is and the molar conductivity is y 10^ 2 ~S ~cm ^ 2 ~mol ^ -1 . At 298 ~K , upon 20 times dilution with water, the molar conductivity of the solution becomes 3 y 10^ 2 ~S ~cm ^ 2 ~mol ^ -1 The value of α is _______ .

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

α = λ m λ m ∘ α 1 = y × 10 + 2 4 × 10 2 = y 4           . . . 1 k a = C 1 α 1 2 1 − α 1             . . . 2 After dilution α 2 = 3 y × 10 2 4 × 10 2 = 3 y 4           . . . 3 k a = C 2 α 2 2 1 − α 2             . . . 4 eq.  1 / 3 ⇒   α 1 α 2 = 1 3 eq  2 / 4 ⇒   1 = C 1 α 1 2 1 − α 2 1 − α 1 C 2 α 2 2 α 1 2 1 − α 2 α 2 2 1 − α 1 = C 2 C 1 C 1 = C 2   20 y 1 2 = C 2 C 1 α 1 2 1 − α 2 α 2 2 1 − α 1 = 1 20 20 α 1 2 1 − α 1 = α 2 2 1 − α 2 20 1 − α 1 = 9 1 − α 2 20 − 60 α 1 = 9 − 9 α 1 11 = 51 α 1 α 1 = 11 51 = 0 .22  

Practice more on Quantrex App →

Related: Chemistry — Electrochemistry · All PYQ Banks