The reaction of 4 -methyloct- 1 -ene ( P , 2 . 52   g ) with HBr in the presence of C 6 H 5 CO 2 O 2 gives two isomeric bromides in a 9 :   1 ratio, with a combined yield of 50 % . Of these, the entire amount of the primary alkyl bromide was reacted with an appropriate amount o

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The reaction of 4 -methyloct- 1 -ene ( P , 2 . 52 &#160; g ) with HBr in the presence of C 6 H 5 CO 2 O 2  gives two isomeric bromides in a 9 : &#160; 1  ratio, with a combined yield of 50 % . Of these, the entire amount of the primary alkyl bromide was reacted with an appropriate amount of diethylamine followed by treatment with aq. K 2 CO 3  to give a non-ionic product S  in 100 % Yield. The mass (in mg ) of S obtained is [Use molar mass (in gmol - 1 ): H = 1 , C = 12 , &#160; N = 14 , Br = 80  ]

Quantrex Academy · Accepted Answer

Correct answer: A. A

The 1-alkene undergo addition reaction and major product formed according to anti-Markonikov's rule. Moles of  P   = Mass &#160; of &#160; P Molar &#160; mass &#160; of &#160; P = 2 . 52 252 = 0 . 01 &#160; mol Given that isomeric bromides formed have the mole fractions  9 10  and  1 10 Moles of  A (major product)  = 0 . 02 &#215; 9 10 &#215; 50 100 = 0 . 009 &#160; mol Now the alkyl bromide formed undergo nucleophilic substitution reaction with diethyl amine and potassium carbonate. In the above reaction, the product  S formed has the molecular weight  = 199 &#160; g &#160; mol - 1 Mass of S = 0 . 009 &#215; 199 = 1 . 791 &#160; g = 1791 &#160; mg

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