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JEE Advanced Chemistry Ionic Equilibrium 2020 JEE Advanced 2020 (Paper 2)

JEE Advanced Chemistry Question (2020) — Solution

Question

An acidified solution of 0 . 05   M   Zn 2 + is saturated with 0 . 1   M   H 2 S . What is the minimum molar concentration ( M ) of H + required to prevent the precipitation of ZnS ? Use K sp ( ZnS ) = 1 . 25 × 10 - 22 and overall dissociation constant of H 2 S ,   K NET = K 1 K 2 = 1 × 10 - 21

Options

  1. A. A
  2. B. B
  3. C. C
  4. D. D

Answer

A. A

Step-by-step solution

For  ZnS K sp ( ZnS ) = Zn 2 + × S 2 - = 1 . 25 × 10 - 22 = 0 . 05 × S 2 - = 1 . 25 × 10 - 22 S 2 - = 25 × 10 - 22 For  H 2 S H 2 S 0 .1   M ⇌ 2 H + + S 2 − 25 × 10 − 22 K a = H ' S 2 - H 2 S = 1 × 10 - 21 = H + 2 × 25 × 10 - 22 0 . 1 = 1 × 10 - 21 H + 2 = 1 25 H + = 1 5 H + = 0 . 2   M  

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