The amount of water produced ( in   g ) in the oxidation of 1 mole   of rhombic sulphur by conc. H N O 3 to a compound with the highest oxidation state of sulphur is (Given data: Molar mass of water = 18   g   m o l - 1 )
A. A
S 8 + 48 HNO 3 → 8 H 2 SO 4 + 48 NO 2 + 16 H 2 O ∵ 1 mol of S 8 produces 16 mole of H 2 O ; ∴ Mass of H 2 O produced ⇒ 16 × 18 ⇒ 288   g
Related: Chemistry — p Block Elements (Group 15, 16, 17 & 18) · All PYQ Banks