Question
At 143   K , the reaction of X e F 4 with O 2 F 2 produces a xenon compound Y . The total number of lone pair(s) of electrons present on the whole molecule of Y is __________
JEE Advanced
Chemistry
p Block Elements (Group 15, 16, 17 & 18)
2019
JEE Advanced 2019 (Paper 1)
JEE Advanced Chemistry Question (2019) — Solution
Options
- A. A
- B. B
- C. C
- D. D
Answer
A. A
Step-by-step solution
XeF 4 + O 2 F 2 → XeF 6 + O 2 So Y is XeF 6 Each F atom contains three lone pairs and Xe atom contain one lone pair. so total lone pair = 3 × 6 + 1 = 19 Total L . P = 19 .
Related: Chemistry — p Block Elements (Group 15, 16, 17 & 18) · All PYQ Banks