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JEE Advanced Chemistry p Block Elements (Group 15, 16, 17 & 18) 2021 JEE Advanced 2021 (Paper 2)

JEE Advanced Chemistry Question (2021) — Solution

Question

Paragraph: The reaction of K _ 3 [ Fe ( CN )_ 6 ] with freshly prepared FeSO _ 4 solution produces a dark blue precipitate called Turnbull's blue. Reaction of K _ 4 [ Fe ( CN )_ 6 ] with the FeSO _ 4 solution in complete absence of air produces a white precipitate X , which turns blue in air. Mixing the FeSO _ 4 solution with NaNO _ 3 , followed by a slow addition of concentrated H _ 2 SO _ 4 through the side of the test tube produces a brown ring. Question: Among the following, the brown ring is due to the formation of

Options

  1. A. Fe NO 2 SO 4 2 2 -
  2. B. Fe NO 2 H 2 O 4 3 +
  3. C. Fe NO 4 SO 4 2
  4. D. Fe NO H 2 O 5 2 +

Answer

D. Fe NO H 2 O 5 2 +

Step-by-step solution

3 Fe 2 + + NO 3 - + 4 H + → NO + 3 Fe 3 + + 2 H 2 O Fe H 2 O 6 2 + + NO → Fe H 2 O 5 NO 2 + Brown   ring + H 2 O

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